10x-0.1x^2=-560-0.2x^2

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Solution for 10x-0.1x^2=-560-0.2x^2 equation: 



10x-0.1x^2=-560-0.2x^2

We move all terms to the left:

10x-0.1x^2-(-560-0.2x^2)=0

We get rid of parentheses

-0.1x^2+0.2x^2+10x+560=0

We add all the numbers together, and all the variables

0.1x^2+10x+560=0

a = 0.1; b = 10; c = +560;
Δ = b2-4ac
Δ = 102-4·0.1·560
Δ = -124
Delta is less than zero, so there is no solution for the equation

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